Why does the following three printf statements print the same value? [duplicate]

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• How come an array's address is equal to its value in C? 7 answers

int data[2][2] = {1,2,3,4};
int (*p)[2];
p = &data[0];
printf("%dn",p);
printf("%dn",data[0]);
printf("%dn",&data[0]);

In this program the value of data[0] and &data[0] returns the same answer. Can anyone provide the explanation?